What is the f(x)=sqrt(4/((x+1)^2)+(x-3)/(x+1)-49) ?

The f(x)=sqrt(4/((x+1)^2)+(x-3)/(x+1)-49) is

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f(x)=sqrt(4/((x+1)^2)+(x-3)/(x+1)-49)

f (x) = \frac{4}{( x + 1 ) ^{2}} + \frac{x - 3}{x + 1} - 49

Domain : - \frac{4}{3} \leq x < - 1 or - 1 < x \leq - \frac{3}{4}

X Intercepts : (- \frac{4}{3}, 0), (- \frac{3}{4}, 0)

Asymptotes : None

Extreme Points : Minimum (- \frac{4}{3}, 0), Minimum (- \frac{3}{4}, 0)

Interval Notation

Domain : [- \frac{4}{3}, - 1) \cup (- 1, - \frac{3}{4}]

Solution steps

Domain of

\frac{4}{( x + 1 ) ^{2}} + \frac{x - 3}{x + 1} - 49 : - \frac{4}{3} \leq x < - 1 or - 1 < x \leq - \frac{3}{4}

Axis interception points of

\frac{4}{( x + 1 ) ^{2}} + \frac{x - 3}{x + 1} - 49 :

X Intercepts

: (- \frac{4}{3}, 0), (- \frac{3}{4}, 0)

Asymptotes of

\frac{4}{( x + 1 ) ^{2}} + \frac{x - 3}{x + 1} - 49 :

None

Extreme Points of

\frac{4}{( x + 1 ) ^{2}} + \frac{x - 3}{x + 1} - 49 :

Minimum

(- \frac{4}{3}, 0),

Minimum

(- \frac{3}{4}, 0)

f (x) = e^{x} - e

f (x) = \frac{4 x - 4}{x + 2}

f (x) = 3 x^{2} - 9

f (x) = - 6^{x}

y = 2 x^{3} - 9 x^{2} + 12 x

What is the f(x)=sqrt(4/((x+1)^2)+(x-3)/(x+1)-49) ?
The f(x)=sqrt(4/((x+1)^2)+(x-3)/(x+1)-49) is