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Popular >

f(x)=x+2ln(x^2+1)

Solution

f (x) = x + 2 ln (x^{2} + 1)

Solution

Domain : - \infty < x < \infty

Range : - \infty < f (x) < \infty

Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : Maximum (- 2 - 3, - 2 - 3 + 2 ln (8 + 43)), Minimum (- 2 + 3, - 2 + 3 + 2 ln (8 - 43))

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

x + 2 ln (x^{2} + 1) : - \infty < x < \infty

Range of

x + 2 ln (x^{2} + 1) : - \infty < f (x) < \infty

Axis interception points of

x + 2 ln (x^{2} + 1) :

Y Intercepts

: (0, 0)

Asymptotes of

x + 2 ln (x^{2} + 1) :

None

Extreme Points of

x + 2 ln (x^{2} + 1) :

Maximum

(- 2 - 3, - 2 - 3 + 2 ln (8 + 43)),

Minimum

(- 2 + 3, - 2 + 3 + 2 ln (8 - 43))

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Frequently Asked Questions (FAQ)

What is the f(x)=x+2ln(x^2+1) ?
The f(x)=x+2ln(x^2+1) is