What is the f(x)=(2x^5+3x^4-x^3+2)/(x^2) ?

The f(x)=(2x^5+3x^4-x^3+2)/(x^2) is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(x)=(2x^5+3x^4-x^3+2)/(x^2)

f (x) = \frac{2 x ^{5} + 3 x ^{4} - x ^{3} + 2}{x ^{2}}

Domain : x < 0 or x > 0

Range : - \infty < f (x) < \infty

X Intercepts : (- 1.85424 \dots, 0)

Asymptotes : Vertical x = 0

Extreme Points : Minimum (0.80386 \dots, 5.26866 \dots)

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{2 x ^{5} + 3 x ^{4} - x ^{3} + 2}{x ^{2}} : x < 0 or x > 0

Range of

\frac{2 x ^{5} + 3 x ^{4} - x ^{3} + 2}{x ^{2}} : - \infty < f (x) < \infty

Axis interception points of

\frac{2 x ^{5} + 3 x ^{4} - x ^{3} + 2}{x ^{2}} :

X Intercepts

: (- 1.85424 \dots, 0)

Asymptotes of

\frac{2 x ^{5} + 3 x ^{4} - x ^{3} + 2}{x ^{2}} :

Vertical

: x = 0

Extreme Points of

\frac{2 x ^{5} + 3 x ^{4} - x ^{3} + 2}{x ^{2}} :

Minimum

(0.80386 \dots, 5.26866 \dots)

f (x) = 2 x^{2} + 6 x - 8

f (x) = \frac{3 x - 2}{4}

f (x) = lo g_{2} (x + 3) + 1

f (x) = 2 x + 1 - \frac{18}{x}

f (x) = x^{2} + 4 x - 16