What is the domain of f(x)=-sqrt(9-x^2) ?

The domain of f(x)=-sqrt(9-x^2) is -3<= x<= 3

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domain of f(x)=-sqrt(9-x^2)

domain

f (x) = - 9 - x^{2}

- 3 \leq x \leq 3

Interval Notation

[- 3, 3]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

The function domain

- 3 \leq x \leq 3

f (x) = \frac{1}{x - 1}

f (x) = x^{2} ln (\frac{x}{6})

f (x) = x + 3 - x

e^{3 x} cos (2 x)

\frac{x + 4}{20}

What is the domain of f(x)=-sqrt(9-x^2) ?
The domain of f(x)=-sqrt(9-x^2) is -3<= x<= 3