What is the extreme f(x)=-x^3+27x-58 ?

The extreme f(x)=-x^3+27x-58 is Minimum(-3,-112),Maximum(3,-4)

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extreme f(x)=-x^3+27x-58

extreme points

f (x) = - x^{3} + 27 x - 58

Minimum (- 3, - 112), Maximum (3, - 4)

Solution steps

f^{'} (x) = - 3 x^{2} + 27

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = - 3

into

- x^{3} + 27 x - 58 : - 112

Minimum (- 3, - 112)

Plug

x = 3

into

- x^{3} + 27 x - 58 : - 4

Maximum (3, - 4)

Minimum (- 3, - 112), Maximum (3, - 4)

(7 + \frac{1}{x}) (\frac{1}{x})

f (x) = 5 x^{2} - \frac{12}{x + 3}

- sin (3 x)

\frac{x}{x - 3}

f (x) = \frac{x + 2}{x + 3}

What is the extreme f(x)=-x^3+27x-58 ?
The extreme f(x)=-x^3+27x-58 is Minimum(-3,-112),Maximum(3,-4)