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Popular >

f(x)=4x^2+x-1

Solution

f (x) = 4 x^{2} + x - 1

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - \frac{17}{16}

X Intercepts : (\frac{- 1 + 17}{8}, 0), (\frac{- 1 - 17}{8}, 0), Y Intercepts : (0, - 1)

Vertex : Minimum (- \frac{1}{8}, - \frac{17}{16})

Inverse : \frac{- 1 + 16 x + 17}{8}, \frac{- 1 - 16 x + 17}{8}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{17}{16}, \infty)

Solution steps

Domain of

4 x^{2} + x - 1 : - \infty < x < \infty

Range of

4 x^{2} + x - 1 : f (x) \geq - \frac{17}{16}

Axis interception points of

4 x^{2} + x - 1 :

X Intercepts

: (\frac{- 1 + 17}{8}, 0), (\frac{- 1 - 17}{8}, 0),

Y Intercepts

: (0, - 1)

Vertex of

4 x^{2} + x - 1 :

Minimum

(- \frac{1}{8}, - \frac{17}{16})

Inverse of

4 x^{2} + x - 1 : \frac{- 1 + 16 x + 17}{8}, \frac{- 1 - 16 x + 17}{8}

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Frequently Asked Questions (FAQ)

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