What is the y=\sqrt[3]{(8x^2-3)/(x^2+2)} ?

The y=\sqrt[3]{(8x^2-3)/(x^2+2)} is

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y=\sqrt[3]{(8x^2-3)/(x^2+2)}

Domain : - \infty < x < \infty

Asymptotes : Horizontal y = 2

Interval Notation

Domain : (- \infty, \infty)

Solution steps

Domain of

Range of

Axis interception points of

X Intercepts

: (\frac{3}{2 2}, 0), (- \frac{3}{2 2}, 0),

Y Intercepts

Asymptotes of

Horizontal

: y = 2

Extreme Points of

Minimum

y = x^{4} + 3 x^{2}

y = (x + 2) (x - 1) (x - 3)^{3}

f (x) = \frac{- 3}{x ^{2} - 1}

y = e^{7 x}

y = x^{2} - 3