en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)= 2/(x+1)+3

Solution

inverse

f (x) = \frac{2}{x + 1} + 3

Solution

\frac{- x + 5}{x - 3}

Solution steps

y = \frac{2}{x + 1} + 3

Replace

x

with

y

x = \frac{2}{y + 1} + 3

Solve for

y, x = \frac{2}{y + 1} + 3

\frac{- x + 5}{x - 3}

Popular Examples

critical-2x^2-2x-2 critical points

- 2 x^{2} - 2 x - 2

inflection-x^4-2x^3+2x^2-5 inflection points

- x^{4} - 2 x^{3} + 2 x^{2} - 5

domain of f(x)=(8+5x)/(x-1)domain

f (x) = \frac{8 + 5 x}{x - 1}

critical f(x)=x^{2/3}(x-4)critical points

f (x) = x^{\frac{2}{3}} (x - 4)

extreme f(x)=5x^5-50x^3+1600 extreme points

f (x) = 5 x^{5} - 50 x^{3} + 1600

Frequently Asked Questions (FAQ)

What is the inverse of f(x)= 2/(x+1)+3 ?
The inverse of f(x)= 2/(x+1)+3 is (-x+5)/(x-3)