What is the y= 1/4 x^2-1/2 ln(x),1<= x<= 2 ?

The y= 1/4 x^2-1/2 ln(x),1<= x<= 2 is

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y= 1/4 x^2-1/2 ln(x),1<= x<= 2

y = \frac{1}{4} x^{2} - \frac{1}{2} ln (x), 1 \leq x \leq 2

Domain : 1 \leq x \leq 2

Range : \frac{1}{4} \leq f (x) \leq 1 - \frac{1}{2} ln (2)

Intercepts : None

Asymptotes : None

Extreme Points : Minimum (1, \frac{1}{4}), Maximum (2, 1 - \frac{1}{2} ln (2))

Interval Notation

Domain : [1, 2]

Range : [\frac{1}{4}, 1 - \frac{1}{2} ln (2)]

Solution steps

Domain of

\frac{1}{4} x^{2} - \frac{1}{2} ln (x), 1 \leq x \leq 2 : 1 \leq x \leq 2

Range of

\frac{1}{4} x^{2} - \frac{1}{2} ln (x), 1 \leq x \leq 2 : \frac{1}{4} \leq f (x) \leq 1 - \frac{1}{2} ln (2)

Axis interception points of

\frac{1}{4} x^{2} - \frac{1}{2} ln (x), 1 \leq x \leq 2 :

None

Asymptotes of

\frac{1}{4} x^{2} - \frac{1}{2} ln (x), 1 \leq x \leq 2 :

None

Extreme Points of

\frac{1}{4} x^{2} - \frac{1}{2} ln (x), 1 \leq x \leq 2 :

Minimum

(1, \frac{1}{4}),

Maximum

(2, 1 - \frac{1}{2} ln (2))

f (x) = \frac{x}{3}

f (y) = y^{2} - 2 y + 4

Y (s) = \frac{4}{s ^{2} - 9}

y = 4 x^{2} - 8 x

f (x) = x^{3} - x^{2} - 20 x

What is the y= 1/4 x^2-1/2 ln(x),1<= x<= 2 ?
The y= 1/4 x^2-1/2 ln(x),1<= x<= 2 is