What is the f(n)=3^{n+2}+(3^{n+3}-3^{n+1}) ?

The f(n)=3^{n+2}+(3^{n+3}-3^{n+1}) is

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f(n)=3^{n+2}+(3^{n+3}-3^{n+1})

f (n) = 3^{n + 2} + (3^{n + 3} - 3^{n + 1})

Domain : - \infty < n < \infty

Range : f (x) > 0

Y Intercepts : (0, 33)

Asymptotes : Horizontal y = 0

Extreme Points : None

Interval Notation

Domain : (- \infty, \infty)

Range : (0, \infty)

Solution steps

Domain of

3^{n + 2} + 3^{n + 3} - 3^{n + 1} : - \infty < n < \infty

Range of

3^{n + 2} + 3^{n + 3} - 3^{n + 1} : f (x) > 0

Axis interception points of

3^{n + 2} + 3^{n + 3} - 3^{n + 1} :

Y Intercepts

: (0, 33)

Asymptotes of

3^{n + 2} + 3^{n + 3} - 3^{n + 1} :

Horizontal

: y = 0

Extreme Points of

3^{n + 2} + 3^{n + 3} - 3^{n + 1} :

None

h (x) = - 2

f (x) = \frac{2 x + 8}{x ^{2} + x - 12}

y = 7 - x^{2}

f (x) = e^{2} x

f (x) = x^{2} - 4 x + 7, - 4 \leq x \leq 5

What is the f(n)=3^{n+2}+(3^{n+3}-3^{n+1}) ?
The f(n)=3^{n+2}+(3^{n+3}-3^{n+1}) is