What is the f(x)=ln(x-1)+e^{x^2-3} ?

The f(x)=ln(x-1)+e^{x^2-3} is Domain: x>1 Intercepts: None Asymptotes: Vertical x=1

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f(x)=ln(x-1)+e^{x^2-3}

f (x) = ln (x - 1) + e^{x^{2} - 3}

Domain : x > 1

Intercepts : None

Asymptotes : Vertical x = 1

Interval Notation

Domain : (1, \infty)

Solution steps

Domain of

ln (x - 1) + e^{x^{2} - 3} : x > 1

Axis interception points of

ln (x - 1) + e^{x^{2} - 3} :

None

Asymptotes of

ln (x - 1) + e^{x^{2} - 3} :

Vertical

: x = 1

f (x) = x^{2} - 4 x + 21

f (m) = m^{3} + 64

f (y) = 3 \cdot y

f (x) = x - 15

g (x) = - 3 x^{3} - 5 x^{2} + 2 x

What is the f(x)=ln(x-1)+e^{x^2-3} ?
The f(x)=ln(x-1)+e^{x^2-3} is Domain: x>1<br/>Intercepts: None<br/>Asymptotes: Vertical x=1