What is the domain of 1/(x-3)+x/2 ,x\ne 3 ?

The domain of 1/(x-3)+x/2 ,x\ne 3 is x 3

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domain of 1/(x-3)+x/2 ,x\ne 3

domain

\frac{1}{x - 3} + \frac{x}{2}, x \neq = 3

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Set the domain to the given interval

x < 3 or x > 3

Find undefined (singularity) points:

No real undefined points

Join undefined points with the domain:

(x < 3 or x > 3) and (x < 3 or x > 3)

x < 3 or x > 3

y = 2 - cos (x)

y = e^{8 x}

p (x) = 3

y = (x + 2)^{2} + 5

f (s) = s^{2} + 2 s + 17

What is the domain of 1/(x-3)+x/2 ,x\ne 3 ?
The domain of 1/(x-3)+x/2 ,x\ne 3 is x<3\lor x>3