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Popular >

f(x)=x^2-1/8 ln(x)

Solution

f (x) = x^{2} - \frac{1}{8} ln (x)

Solution

Domain : x > 0

Range : f (x) \geq \frac{1}{16} + \frac{1}{4} ln (2)

Intercepts : None

Asymptotes : Vertical x = 0

Extreme Points : Minimum (\frac{1}{4}, \frac{1}{16} + \frac{1}{4} ln (2))

+1

Interval Notation

Domain : (0, \infty)

Range : [\frac{1}{16} + \frac{1}{4} ln (2), \infty)

Solution steps

Domain of

x^{2} - \frac{1}{8} ln (x) : x > 0

Range of

x^{2} - \frac{1}{8} ln (x) : f (x) \geq \frac{1}{16} + \frac{1}{4} ln (2)

Axis interception points of

x^{2} - \frac{1}{8} ln (x) :

None

Asymptotes of

x^{2} - \frac{1}{8} ln (x) :

Vertical

: x = 0

Extreme Points of

x^{2} - \frac{1}{8} ln (x) :

Minimum

(\frac{1}{4}, \frac{1}{16} + \frac{1}{4} ln (2))

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f (x) = \frac{x ^{2} + 2 x + 1}{x - 1}

f (x) = \frac{2}{3} x - 6

Frequently Asked Questions (FAQ)

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