What is the f(y)=(\sqrt[3]{2}-\sqrt[3]{y})/(y^2-4) ?

The f(y)=(\sqrt[3]{2}-\sqrt[3]{y})/(y^2-4) is

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f(y)=(\sqrt[3]{2}-\sqrt[3]{y})/(y^2-4)

Domain : y < - 2 or - 2 < y < 2 or y > 2

Y Intercepts : (0, - \frac{1}{2 \cdot 2 ^{\frac{2}{3}}})

Asymptotes : Horizontal y = 0

Extreme Points : None

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Domain of

Axis interception points of

Y Intercepts

: (0, - \frac{1}{2 \cdot 2 ^{\frac{2}{3}}})

Asymptotes of

Horizontal

: y = 0

Extreme Points of

None

r, r = 4 tan (θ) sec (θ)

f (x) = \frac{18 - 11 x + x ^{2}}{x - 2}

y = - \frac{1}{2} cos (x)

y = x + ln (x)

f (x) = 2 lo g_{3} (2 x + 4) - 1

What is the f(y)=(\sqrt[3]{2}-\sqrt[3]{y})/(y^2-4) ?
The f(y)=(\sqrt[3]{2}-\sqrt[3]{y})/(y^2-4) is