What is the monotone f(x)=x^4+x^3-4x^2+5 ?

The monotone f(x)=x^4+x^3-4x^2+5 is

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monotone f(x)=x^4+x^3-4x^2+5

monotone intervals

f (x) = x^{4} + x^{3} - 4 x^{2} + 5

Decreasing : - \infty < x < \frac{- 3 - 137}{8}, Increasing : \frac{- 3 - 137}{8} < x < 0, Decreasing : 0 < x < \frac{137 - 3}{8}, Increasing : \frac{137 - 3}{8} < x < \infty

Solution steps

f^{'} (x) = 4 x^{3} + 3 x^{2} - 8 x

Find intervals:

Decreasing

: - \infty < x < \frac{- 3 - 137}{8},

Increasing

: \frac{- 3 - 137}{8} < x < 0,

Decreasing

: 0 < x < \frac{137 - 3}{8},

Increasing

: \frac{137 - 3}{8} < x < \infty

Decreasing : - \infty < x < \frac{- 3 - 137}{8}, Increasing : \frac{- 3 - 137}{8} < x < 0, Decreasing : 0 < x < \frac{137 - 3}{8}, Increasing : \frac{137 - 3}{8} < x < \infty

f (x) = \frac{4 x ^{2}}{x ^{2} - 9}

2 x + 5 y + 20 = 0

f (x) = \frac{x ^{2} + 5 x - 6}{x ^{2} - 5 x - 6}

\frac{- 2 - 5 x}{3 x - 1}

f (x) = - \frac{1}{x ^{2} + 7}