What is the f(x)=(5x^3-6x^2-8x+9)/(x^4+2x^3+x+1) ?

The f(x)=(5x^3-6x^2-8x+9)/(x^4+2x^3+x+1) is

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f(x)=(5x^3-6x^2-8x+9)/(x^4+2x^3+x+1)

f (x) = \frac{5 x ^{3} - 6 x ^{2} - 8 x + 9}{x ^{4} + 2 x ^{3} + x + 1}

Domain : x < - 2.11768 \dots or - 2.11768 \dots < x < - 0.64144 \dots or x > - 0.64144 \dots

Range : - 1.61943 E 15 < f (x) < 7.08573 E 15

X Intercepts : (1, 0), (\frac{1 + 181}{10}, 0), (\frac{1 - 181}{10}, 0), Y Intercepts : (0, 9)

Asymptotes : Vertical x = - 2.11768 \dots, x = - 0.64144 \dots, Horizontal y = 0

Extreme Points : Minimum (1.18108 \dots, - 0.07822 \dots), Maximum (4.08928 \dots, 0.51689 \dots)

Interval Notation

Domain : (- \infty, - 2.11768 \dots) \cup (- 2.11768 \dots, - 0.64144 \dots) \cup (- 0.64144 \dots, \infty)

Range : (- 1.61943 E 15, 7.08573 E 15)

Solution steps

Domain of

\frac{5 x ^{3} - 6 x ^{2} - 8 x + 9}{x ^{4} + 2 x ^{3} + x + 1} : x < - 2.11768 \dots or - 2.11768 \dots < x < - 0.64144 \dots or x > - 0.64144 \dots

Range of

\frac{5 x ^{3} - 6 x ^{2} - 8 x + 9}{x ^{4} + 2 x ^{3} + x + 1} : - 1.61943 E 15 < f (x) < 7.08573 E 15

Axis interception points of

\frac{5 x ^{3} - 6 x ^{2} - 8 x + 9}{x ^{4} + 2 x ^{3} + x + 1} :

X Intercepts

: (1, 0), (\frac{1 + 181}{10}, 0), (\frac{1 - 181}{10}, 0),

Y Intercepts

: (0, 9)

Asymptotes of

\frac{5 x ^{3} - 6 x ^{2} - 8 x + 9}{x ^{4} + 2 x ^{3} + x + 1} :

Vertical

: x = - 2.11768 \dots, x = - 0.64144 \dots,

Horizontal

: y = 0

Extreme Points of

\frac{5 x ^{3} - 6 x ^{2} - 8 x + 9}{x ^{4} + 2 x ^{3} + x + 1} :

Minimum

(1.18108 \dots, - 0.07822 \dots),

Maximum

(4.08928 \dots, 0.51689 \dots)

g (x) = lo g_{3} (x - 1)

f (x) = \frac{5 x ^{2} - 5}{- 3 x ^{2} - 6 x + 9}

f (x) = 2 e^{4 x}

f (x) = x^{4} - 2 x^{2} - 1

f (x) = ∣ 4 - x ∣

What is the f(x)=(5x^3-6x^2-8x+9)/(x^4+2x^3+x+1) ?
The f(x)=(5x^3-6x^2-8x+9)/(x^4+2x^3+x+1) is