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Popular >

f(x)=0.5x^2-10x+200

Solution

f (x) = 0.5 x^{2} - 10 x + 200

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq 150

Y Intercepts : (0, 200)

Vertex : Minimum (10, 150)

Inverse : \frac{100 + 200 x - 30000}{10}, \frac{100 - 200 x - 30000}{10}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [150, \infty)

Solution steps

Domain of

0.5 x^{2} - 10 x + 200 : - \infty < x < \infty

Range of

0.5 x^{2} - 10 x + 200 : f (x) \geq 150

Axis interception points of

0.5 x^{2} - 10 x + 200 :

Y Intercepts

: (0, 200)

Vertex of

0.5 x^{2} - 10 x + 200 :

Minimum

(10, 150)

Inverse of

0.5 x^{2} - 10 x + 200 : \frac{100 + 200 x - 30000}{10}, \frac{100 - 200 x - 30000}{10}

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Frequently Asked Questions (FAQ)

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