What is the inverse of f(x)=2x^2+24x+76,-6<= x<= 2 ?

The inverse of f(x)=2x^2+24x+76,-6<= x<= 2 is (-24+sqrt(8x-32))/4 ,(-24-sqrt(8x-32))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2x^2+24x+76,-6<= x<= 2

inverse

f (x) = 2 x^{2} + 24 x + 76, - 6 \leq x \leq 2

\frac{- 24 + 8 x - 32}{4}, \frac{- 24 - 8 x - 32}{4}

Solution steps

y = 2 x^{2} + 24 x + 76

Replace

x

with

y

x = 2 y^{2} + 24 y + 76

Solve for

y, x = 2 y^{2} + 24 y + 76

\frac{- 24 + 8 x - 32}{4}, \frac{- 24 - 8 x - 32}{4}

\frac{3 x - 5}{4 x + 13}

f (x) = \frac{2 x + 5}{3}

f (x) = 1 - 3 x

f (x) = x^{\frac{2}{3}}

f (x) = 2 x^{3} - 3 x^{2} + 9 x - 6

What is the inverse of f(x)=2x^2+24x+76,-6<= x<= 2 ?
The inverse of f(x)=2x^2+24x+76,-6<= x<= 2 is (-24+sqrt(8x-32))/4 ,(-24-sqrt(8x-32))/4