What is the critical y=(5x)/(x^2+25) ?

The critical y=(5x)/(x^2+25) is x=-5,x=5

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critical y=(5x)/(x^2+25)

critical points

y = \frac{5 x}{x ^{2} + 25}

x = - 5, x = 5

Solution steps

\frac{5 x}{x ^{2} + 25}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5, x = 5

Identify critical points not in

f (x)

domain

Domain of

\frac{5 x}{x ^{2} + 25} : - \infty < x < \infty

All critical points are in domain

x = - 5, x = 5

3 x + 2 y = 4

f (x) = 3 x^{e} - 2

\frac{3 + x}{x - 2}

(3 x^{2} - 31 x + 56) - (x - 8)

f (x) = (x - 2)^{2} + (y - 6)^{2} = 25