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Popular >

f(θ)=2tan^2(θ)+1

Solution

f (θ) = 2 tan^{2} (θ) + 1

Solution

Period : π

Domain : πn \leq θ < \frac{π}{2} + πn or \frac{π}{2} + πn < θ < π + πn

Range : f (θ) \geq 1

Y Intercepts : (0, 1)

Asymptotes : Vertical θ = \frac{π}{2} + πn

Extreme Points : Minimum (πn, 1)

+1

Interval Notation

Domain : [πn, \frac{π}{2} + πn) \cup (\frac{π}{2} + πn, π + πn)

Range : [1, \infty)

Solution steps

Periodicity of

2 tan^{2} (θ) + 1 : π

Domain of

2 tan^{2} (θ) + 1 : πn \leq θ < \frac{π}{2} + πn or \frac{π}{2} + πn < θ < π + πn

Range of

2 tan^{2} (θ) + 1 : f (θ) \geq 1

Axis interception points of

2 tan^{2} (θ) + 1 :

Y Intercepts

: (0, 1)

Asymptotes of

2 tan^{2} (θ) + 1 :

Vertical

: θ = \frac{π}{2} + πn

Extreme Points of

2 tan^{2} (θ) + 1 :

Minimum

(πn, 1)

Popular Examples

y = 6 x^{2} + 8 x + 4

y = - x^{2} - 12 x - 44

y=log_{5}(6x+4)

y = lo g_{5} (6 x + 4)

y = \frac{1}{2} (x + 3)

f(x)=sqrt(2x^2+6)

f (x) = 2 x^{2} + 6

Frequently Asked Questions (FAQ)

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