What is the perpendicular y=2x+3,(4,7) ?

The perpendicular y=2x+3,(4,7) is y=-1/2 x+9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular y=2x+3,(4,7)

perpendicular

y = 2 x + 3, (4, 7)

y = - \frac{1}{2} x + 9

Solution steps

Find the line

y = mx + b

perpendicular to

y = 2 x + 3

that passes through

(4, 7)

Find the slope of

y = 2 x + 3 : m = 2

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(4, 7) : y = - \frac{1}{2} x + 9

y = - \frac{1}{2} x + 9

- 5 x + 2 y = 7

f (x) = x^{5} - 5 x^{4}

f (x) = \frac{x ^{2} - x + 6}{x + 3}

(0, 1), (8, 7)

- 2.318 + 0.2356 x - 0.002674 x^{2}

What is the perpendicular y=2x+3,(4,7) ?
The perpendicular y=2x+3,(4,7) is y=-1/2 x+9