What is the critical f(x)=xsqrt(4-x) ?

The critical f(x)=xsqrt(4-x) is x= 8/3 ,x=4

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critical f(x)=xsqrt(4-x)

critical points

f (x) = x 4 - x

x = \frac{8}{3}, x = 4

Solution steps

x 4 - x

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{8}{3}, x = 4

Identify critical points not in

f (x)

domain

Domain of

x 4 - x : x \leq 4

All critical points are in domain

x = \frac{8}{3}, x = 4

f (x) = (x - 2)^{2} - 4

f (x) = 2 x^{2} + 4 x - 1

x + 2 - 6

f (x) = x^{3} + 9

f (x) = \frac{x - 5}{2 x + 3}

What is the critical f(x)=xsqrt(4-x) ?
The critical f(x)=xsqrt(4-x) is x= 8/3 ,x=4