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Popular >

extreme f(x)=sqrt(x^2+1)

Solution

extreme points

f (x) = x^{2} + 1

Solution

Minimum (0, 1)

Solution steps

f^{'} (x) = \frac{x}{x ^{2} + 1}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{2} + 1 : 1

Minimum (0, 1)

Popular Examples

inverse of f(x)=(5x+1)/(2-5x)inverse

f (x) = \frac{5 x + 1}{2 - 5 x}

domain of sqrt(3x-7)domain

3 x - 7

inflection f(x)=-4x^3+12x^2-2 inflection points

f (x) = - 4 x^{3} + 12 x^{2} - 2

asymptotes of f(x)=(-2x^2-13x+35)/(x-1)asymptotes

f (x) = \frac{- 2 x ^{2} - 13 x + 35}{x - 1}

parity h(t)= 1/(t^3+2)parity

h (t) = \frac{1}{t ^{3} + 2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=sqrt(x^2+1) ?
The extreme f(x)=sqrt(x^2+1) is Minimum(0,1)