What is the f(x)=sqrt(2x+5+2\sqrt{x^2+5x+6)} ?

The f(x)=sqrt(2x+5+2\sqrt{x^2+5x+6)} is

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f(x)=sqrt(2x+5+2\sqrt{x^2+5x+6)}

f (x) = 2 x + 5 + 2 x^{2} + 5 x + 6

Domain : x \geq - 2

Range : f (x) \geq 1

Y Intercepts : (0, 5 + 26)

Asymptotes : None

Extreme Points : Minimum (- 2, 1)

Interval Notation

Domain : [- 2, \infty)

Range : [1, \infty)

Solution steps

Domain of

2 x + 5 + 2 x^{2} + 5 x + 6 : x \geq - 2

Range of

2 x + 5 + 2 x^{2} + 5 x + 6 : f (x) \geq 1

Axis interception points of

2 x + 5 + 2 x^{2} + 5 x + 6 :

Y Intercepts

: (0, 5 + 26)

Asymptotes of

2 x + 5 + 2 x^{2} + 5 x + 6 :

None

Extreme Points of

2 x + 5 + 2 x^{2} + 5 x + 6 :

Minimum

(- 2, 1)

f (x) = x^{2} + 4 x + 24

f (x) = x^{4} + 21 x^{2} - 100

f (x) = sec (5 x)

f (x) = (\frac{1}{2})^{x} + 2

f (x) = 36 x

What is the f(x)=sqrt(2x+5+2\sqrt{x^2+5x+6)} ?
The f(x)=sqrt(2x+5+2\sqrt{x^2+5x+6)} is