What is the asymptotes of f(x)=(x^2-4x+1)/(x-1) ?

The asymptotes of f(x)=(x^2-4x+1)/(x-1) is Vertical: x=1,Slant: y=x-3

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asymptotes of f(x)=(x^2-4x+1)/(x-1)

asymptotes

f (x) = \frac{x ^{2} - 4 x + 1}{x - 1}

Vertical : x = 1, Slant : y = x - 3

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4 x + 1}{x - 1} : x = 1

Horizontal Asymptotes of

\frac{x ^{2} - 4 x + 1}{x - 1} :

None

Slant Asymptotes of

\frac{x ^{2} - 4 x + 1}{x - 1} : y = x - 3

Vertical : x = 1, Slant : y = x - 3

f (x) = 3 cos (x)

f (x) = 8 - 5 x^{2}

f (x) = - x^{3} + 12 x - 16

f (x) = \frac{x ^{2} + 3 x - 18}{x - 6}

x^{3} - 3 x^{2}

What is the asymptotes of f(x)=(x^2-4x+1)/(x-1) ?
The asymptotes of f(x)=(x^2-4x+1)/(x-1) is Vertical: x=1,Slant: y=x-3