What is the f(x)=(x^2+4x-5)/(2x^5-6x^4+4x^2) ?

The f(x)=(x^2+4x-5)/(2x^5-6x^4+4x^2) is

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f(x)=(x^2+4x-5)/(2x^5-6x^4+4x^2)

f (x) = \frac{x ^{2} + 4 x - 5}{2 x ^{5} - 6 x ^{4} + 4 x ^{2}}

Domain : x < 1 - 3 or 1 - 3 < x < 0 or 0 < x < 1 or 1 < x < 1 + 3 or x > 1 + 3

Range : f (x) \leq - 0.43564 \dots or f (x) \geq - 0.00033 \dots

X Intercepts : (- 5, 0)

Asymptotes : Vertical x = 1 - 3, x = 0, x = 1 + 3, Horizontal y = 0

Extreme Points : Minimum (- 6.76450 \dots, - 0.00033 \dots), Maximum (- 0.50817 \dots, - 11.98902 \dots), Maximum (1.93934 \dots, - 0.43564 \dots)

Interval Notation

Domain : (- \infty, 1 - 3) \cup (1 - 3, 0) \cup (0, 1) \cup (1, 1 + 3) \cup (1 + 3, \infty)

Range : (- \infty, - 0.43564 \dots] \cup [- 0.00033 \dots, \infty)

Solution steps

Domain of

\frac{x ^{2} + 4 x - 5}{2 x ^{5} - 6 x ^{4} + 4 x ^{2}} : x < 1 - 3 or 1 - 3 < x < 0 or 0 < x < 1 or 1 < x < 1 + 3 or x > 1 + 3

Range of

\frac{x ^{2} + 4 x - 5}{2 x ^{5} - 6 x ^{4} + 4 x ^{2}} : f (x) \leq - 0.43564 \dots or f (x) \geq - 0.00033 \dots

Axis interception points of

\frac{x ^{2} + 4 x - 5}{2 x ^{5} - 6 x ^{4} + 4 x ^{2}} :

X Intercepts

: (- 5, 0)

Asymptotes of

\frac{x ^{2} + 4 x - 5}{2 x ^{5} - 6 x ^{4} + 4 x ^{2}} :

Vertical

: x = 1 - 3, x = 0, x = 1 + 3,

Horizontal

: y = 0

Extreme Points of

\frac{x ^{2} + 4 x - 5}{2 x ^{5} - 6 x ^{4} + 4 x ^{2}} :

Minimum

(- 6.76450 \dots, - 0.00033 \dots),

Maximum

(- 0.50817 \dots, - 11.98902 \dots),

Maximum

(1.93934 \dots, - 0.43564 \dots)

y = x^{\frac{5}{3}} - 5 x^{\frac{2}{3}}

f (x) = 2 x^{3} + 7 x^{2} + 2 x - 3

f (x) = sec (x) - csc (x)

g (x) = - 2 x

f (x) = 7 x + 13

What is the f(x)=(x^2+4x-5)/(2x^5-6x^4+4x^2) ?
The f(x)=(x^2+4x-5)/(2x^5-6x^4+4x^2) is