What is the inverse of y= 1/4*2^{x-20}+2 ?

The inverse of y= 1/4*2^{x-20}+2 is (ln(4x-8))/(ln(2))+20

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inverse of y= 1/4*2^{x-20}+2

inverse

y = \frac{1}{4} \cdot 2^{x - 20} + 2

\frac{ln ( 4 x - 8 )}{ln ( 2 )} + 20

Solution steps

y = \frac{1}{4} \cdot 2^{x - 20} + 2

Replace

x

with

y

x = \frac{1}{4} \cdot 2^{y - 20} + 2

Solve for

y, x = \frac{1}{4} \cdot 2^{y - 20} + 2

\frac{ln ( 4 x - 8 )}{ln ( 2 )} + 20

f (x) = \frac{x + 1}{2 x + 1}

\frac{2 x + 3}{4}

f (x) = \frac{3 x - 1}{2 x + 5}

f (x) = (\frac{4}{x}) (\frac{6}{x + 6})

f (x) = \frac{2 - x}{x ^{2} - 1}

What is the inverse of y= 1/4*2^{x-20}+2 ?
The inverse of y= 1/4*2^{x-20}+2 is (ln(4x-8))/(ln(2))+20