What is the domain of f(x)=(sqrt(x+1))/(x-7) ?

The domain of f(x)=(sqrt(x+1))/(x-7) is -1 7

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domain of f(x)=(sqrt(x+1))/(x-7)

domain

f (x) = \frac{x + 1}{x - 7}

- 1 \leq x < 7 or x > 7

Interval Notation

[- 1, 7) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

- 1 \leq x < 7 or x > 7

f (x) = (x + 4)^{3} - 2

f (x) = 2 sin (x)

x y = 7

f (x) = \frac{3 x - 4}{4 x + 9}

f (x) = x^{3} - 6 x^{2} + 5

What is the domain of f(x)=(sqrt(x+1))/(x-7) ?
The domain of f(x)=(sqrt(x+1))/(x-7) is -1<= x<7\lor x>7