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Popular >

f(x)=ln(x^2)+(1/4)e^{2x}

Solution

f (x) = ln (x^{2}) + (\frac{1}{4}) e^{2 x}

Solution

Domain : x < 0 or x > 0

Intercepts : None

Asymptotes : Vertical x = 0

Extreme Points : None

+1

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

ln (x^{2}) + \frac{1}{4} e^{2 x} : x < 0 or x > 0

Axis interception points of

ln (x^{2}) + \frac{1}{4} e^{2 x} :

None

Asymptotes of

ln (x^{2}) + \frac{1}{4} e^{2 x} :

Vertical

: x = 0

Extreme Points of

ln (x^{2}) + \frac{1}{4} e^{2 x} :

None

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y = \frac{- 2}{3} x + 1

Frequently Asked Questions (FAQ)

What is the f(x)=ln(x^2)+(1/4)e^{2x} ?
The f(x)=ln(x^2)+(1/4)e^{2x} is