What is the inverse of f(x)= 1/3 x^3 ?

The inverse of f(x)= 1/3 x^3 is cube root of 3}\sqrt[3]{x

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inverse of f(x)= 1/3 x^3

inverse

f (x) = \frac{1}{3} x^{3}

Solution steps

y = \frac{1}{3} x^{3}

Replace

x

with

y

x = \frac{1}{3} y^{3}

Solve for

y, x = \frac{1}{3} y^{3}

f (x) = 5 x - 2 y = 10

(- 1, - 9), (5, 9)

f (x) = - e^{x}

\frac{- x ^{2} + 1}{( x ^{2} + 1 ) ^{2}}

f (x) = - 2 x^{2} + 4 x

What is the inverse of f(x)= 1/3 x^3 ?
The inverse of f(x)= 1/3 x^3 is cube root of 3}\sqrt[3]{x