What is the domain of f(x)=((x^2-9))/(x-3) ?

The domain of f(x)=((x^2-9))/(x-3) is x 3

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domain of f(x)=((x^2-9))/(x-3)

domain

f (x) = \frac{( x ^{2} - 9 )}{x - 3}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

\frac{( 9 + x )}{9 - x}

f (x) = x + 1

f (x) = \frac{x - 5}{x + 1}

f (x) = x^{2} - 5 x

x^{2} - 18 x + 73

What is the domain of f(x)=((x^2-9))/(x-3) ?
The domain of f(x)=((x^2-9))/(x-3) is x<3\lor x>3