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Popular >

f(θ)=sin^2(θ)-2sin(θ)+1

Solution

f (θ) = sin^{2} (θ) - 2 sin (θ) + 1

Solution

Period : 2 π

Domain : - \infty < θ < \infty

Range : 0 \leq f (θ) \leq 4

X Intercepts : (\frac{π}{2} + 2 πn, 0), Y Intercepts : (0, 1)

Asymptotes : None

Extreme Points : Minimum (\frac{π}{2} + 2 πn, 0), Maximum (\frac{3 π}{2} + 2 πn, 4)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [0, 4]

Solution steps

Periodicity of

sin^{2} (θ) - 2 sin (θ) + 1 : 2 π

Domain of

sin^{2} (θ) - 2 sin (θ) + 1 : - \infty < θ < \infty

Range of

sin^{2} (θ) - 2 sin (θ) + 1 : 0 \leq f (θ) \leq 4

Axis interception points of

sin^{2} (θ) - 2 sin (θ) + 1 :

X Intercepts

: (\frac{π}{2} + 2 πn, 0),

Y Intercepts

: (0, 1)

Asymptotes of

sin^{2} (θ) - 2 sin (θ) + 1 :

None

Extreme Points of

sin^{2} (θ) - 2 sin (θ) + 1 :

Minimum

(\frac{π}{2} + 2 πn, 0),

Maximum

(\frac{3 π}{2} + 2 πn, 4)

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y = 2 sin (x) + 3 cos (x)

Frequently Asked Questions (FAQ)

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