What is the shift f(t)=sin(2t-pi/3)+1 ?

The shift f(t)=sin(2t-pi/3)+1 is Phase: pi/6 , Vertical:1

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shift f(t)=sin(2t-pi/3)+1

shift

f (t) = sin (2 t - \frac{π}{3}) + 1

Phase : \frac{π}{6}, Vertical : 1

Solution steps

f (x) = sin (2 t - \frac{π}{3}) + 1

g (B x - C) = sin (2 t - \frac{π}{3}), B = 2, C = \frac{π}{3}, D = 1

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{π}{3}}{2}

\frac{π}{6}

The vertical shift

D

1

1

(12.13) (0.4)

\frac{x + 6}{x ^{2} - 36}

f (x) = x^{2} - 5 x + 2

f (x) = \frac{5 x}{x ^{2} - 4}

- 2 x + y = 1

What is the shift f(t)=sin(2t-pi/3)+1 ?
The shift f(t)=sin(2t-pi/3)+1 is Phase: pi/6 , Vertical:1