What is the f(x)= 1/(x+1)+1/(x-1),x\ne-1,1 ?

The f(x)= 1/(x+1)+1/(x-1),x\ne-1,1 is

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f(x)= 1/(x+1)+1/(x-1),x\ne-1,1

f (x) = \frac{1}{x + 1} + \frac{1}{x - 1}, x \neq = - 1, 1

Domain : x < - 1 or - 1 < x < 1 or x > 1

Range : - \infty < f (x) < \infty

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = 1, Horizontal y = 0

Extreme Points : None

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{1}{x + 1} + \frac{1}{x - 1}, x \neq = - 1 : x < - 1 or - 1 < x < 1 or x > 1

Range of

\frac{1}{x + 1} + \frac{1}{x - 1}, x \neq = - 1 : - \infty < f (x) < \infty

Axis interception points of

\frac{1}{x + 1} + \frac{1}{x - 1}, x \neq = - 1 :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{1}{x + 1} + \frac{1}{x - 1}, x \neq = - 1 :

Vertical

: x = 1,

Horizontal

: y = 0

Extreme Points of

\frac{1}{x + 1} + \frac{1}{x - 1}, x \neq = - 1 :

None

f (x) = 3 x^{4} + 2 x^{3} - x + 15

y = - (x + 2) (x - 4)

f (x) = - 3 (x - 1) (x + 2)

f (x) = 1 0^{x} lo g_{10} (x)

f (x) = sin^{2} (\frac{x}{2}) cos^{2} (\frac{x}{2})

What is the f(x)= 1/(x+1)+1/(x-1),x\ne-1,1 ?
The f(x)= 1/(x+1)+1/(x-1),x\ne-1,1 is