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Popular >

f(x)=6sin^2(2x+pi/8)+5

Solution

f (x) = 6 sin^{2} (2 x + \frac{π}{8}) + 5

Solution

Period : \frac{π}{2}

Domain : - \infty < x < \infty

Range : 5 \leq f (x) \leq 11

Y Intercepts : (0, - \frac{3 2}{2} + 8)

Asymptotes : None

Extreme Points : Maximum (\frac{3 π}{16} + \frac{π}{2} n, 11), Minimum (\frac{7 π}{16} + \frac{π}{2} n, 5)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [5, 11]

Solution steps

Periodicity of

6 sin^{2} (2 x + \frac{π}{8}) + 5 : \frac{π}{2}

Domain of

6 sin^{2} (2 x + \frac{π}{8}) + 5 : - \infty < x < \infty

Range of

6 sin^{2} (2 x + \frac{π}{8}) + 5 : 5 \leq f (x) \leq 11

Axis interception points of

6 sin^{2} (2 x + \frac{π}{8}) + 5 :

Y Intercepts

: (0, - \frac{3 2}{2} + 8)

Asymptotes of

6 sin^{2} (2 x + \frac{π}{8}) + 5 :

None

Extreme Points of

6 sin^{2} (2 x + \frac{π}{8}) + 5 :

Maximum

(\frac{3 π}{16} + \frac{π}{2} n, 11),

Minimum

(\frac{7 π}{16} + \frac{π}{2} n, 5)

Popular Examples

f (x) = 2 x^{2} - 5 x - 6

f(x)=sqrt(x^2-3x-10)

f (x) = x^{2} - 3 x - 10

f(θ)=5+2cos(3θ)

f (θ) = 5 + 2 cos (3 θ)

f(x)=-2x^2+3x+2

f (x) = - 2 x^{2} + 3 x + 2

f(x)=2cos(x)+sin(x)

f (x) = 2 cos (x) + sin (x)

Frequently Asked Questions (FAQ)

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