What is the inverse of f(x)= 6/(sqrt(8-x)) ?

The inverse of f(x)= 6/(sqrt(8-x)) is -(36-8x^2)/(x^2)

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inverse of f(x)= 6/(sqrt(8-x))

inverse

f (x) = \frac{6}{8 - x}

- \frac{36 - 8 x ^{2}}{x ^{2}}

Solution steps

y = \frac{6}{8 - x}

Replace

x

with

y

x = \frac{6}{8 - y}

Solve for

y, x = \frac{6}{8 - y}

- \frac{36 - 8 x ^{2}}{x ^{2}}

f (x) = 2 x^{2} + 8 x - 10

y = 3 x - 9

f (x) = \frac{x + 5}{x - 6}

f (x) = - 3 x + 15

f (x) = x - \frac{2}{x}

What is the inverse of f(x)= 6/(sqrt(8-x)) ?
The inverse of f(x)= 6/(sqrt(8-x)) is -(36-8x^2)/(x^2)