What is the f(x)=log_{3}(5x+4)+log_{3}(x^2+2) ?

The f(x)=log_{3}(5x+4)+log_{3}(x^2+2) is

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f(x)=log_{3}(5x+4)+log_{3}(x^2+2)

f (x) = lo g_{3} (5 x + 4) + lo g_{3} (x^{2} + 2)

Domain : x > - \frac{4}{5}

Range : - \infty < f (x) < \infty

X Intercepts : (- 0.72061 \dots, 0), Y Intercepts : (0, 3 lo g_{3} (2))

Asymptotes : Vertical x = - \frac{4}{5}

Extreme Points : None

Interval Notation

Domain : (- \frac{4}{5}, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

lo g_{3} (5 x + 4) + lo g_{3} (x^{2} + 2) : x > - \frac{4}{5}

Range of

lo g_{3} (5 x + 4) + lo g_{3} (x^{2} + 2) : - \infty < f (x) < \infty

Axis interception points of

lo g_{3} (5 x + 4) + lo g_{3} (x^{2} + 2) :

X Intercepts

: (- 0.72061 \dots, 0),

Y Intercepts

: (0, 3 lo g_{3} (2))

Asymptotes of

lo g_{3} (5 x + 4) + lo g_{3} (x^{2} + 2) :

Vertical

: x = - \frac{4}{5}

Extreme Points of

lo g_{3} (5 x + 4) + lo g_{3} (x^{2} + 2) :

None

f (t) = - 10 t^{2} + 24 t + 5.6

f (x) = (1 + 2 x)^{\frac{1}{5}}

y = 2 (4.5)^{x}

f (x) = \frac{x ^{3} + 3}{x + 3}

f (t) = \frac{t}{1 + t ^{2}}

What is the f(x)=log_{3}(5x+4)+log_{3}(x^2+2) ?
The f(x)=log_{3}(5x+4)+log_{3}(x^2+2) is