What is the y=-2/3 sin(1/3)(x-(3pi)/4)+2 ?

The y=-2/3 sin(1/3)(x-(3pi)/4)+2 is

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y=-2/3 sin(1/3)(x-(3pi)/4)+2

y = - \frac{2}{3} sin (\frac{1}{3}) (x - \frac{3 π}{4}) + 2

Y Intercepts : (0, - \frac{2}{3} sin (\frac{1}{3}) (0 - \frac{3 π}{4}) + 2)

Slope : m = - \frac{2 sin ( \frac{1}{3} )}{3}

Inverse : None

Domain : - \infty < x < \infty

Range : - \infty < f (x) < \infty

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Axis interception points of

- \frac{2}{3} sin (\frac{1}{3}) (x - \frac{3 π}{4}) + 2 :

Y Intercepts

: (0, - \frac{2}{3} sin (\frac{1}{3}) (0 - \frac{3 π}{4}) + 2)

Slope of

- \frac{2}{3} sin (\frac{1}{3}) (x - \frac{3 π}{4}) + 2 : m = - \frac{2 sin ( \frac{1}{3} )}{3}

Inverse of

- \frac{2}{3} sin (\frac{1}{3}) (x - \frac{3 π}{4}) + 2 :

None

Domain of

- \frac{2}{3} sin (\frac{1}{3}) (x - \frac{3 π}{4}) + 2 : - \infty < x < \infty

Range of

- \frac{2}{3} sin (\frac{1}{3}) (x - \frac{3 π}{4}) + 2 : - \infty < f (x) < \infty

f (x) = arctan (2 x) - ∣ x + 1 ∣

f (v) = 3 v^{2}

f (m) = m^{2} + 3 m - 4

f (X) = lo g_{3} (X)

f (m) = m^{2} + 5 m - 24