What is the distance (-11,15),(9,-12) ?

The distance (-11,15),(9,-12) is square root of 1129

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distance (-11,15),(9,-12)

distance

(- 11, 15), (9, - 12)

1129

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 11, 15)

and

(9, - 12)

= (9 - (- 11))^{2} + (- 12 - 15)^{2}

Simplify

= 1129

f (x) = e^{x - 2} - 3

f (x) = 3^{- x}

f (x) = \frac{x ^{2} + 4}{x}

y = \frac{3}{4} x + 3, (3, - 3)

(x - 2)^{2} (x - 1)

What is the distance (-11,15),(9,-12) ?
The distance (-11,15),(9,-12) is square root of 1129