What is the inflection x^4-32x^2+5 ?

The inflection x^4-32x^2+5 is (-4/(sqrt(3)),-1235/9),(4/(sqrt(3)),-1235/9)

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inflection x^4-32x^2+5

inflection points

x^{4} - 32 x^{2} + 5

(- \frac{4}{3}, - \frac{1235}{9}), (\frac{4}{3}, - \frac{1235}{9})

Solution steps

f^{''} (x) = 12 x^{2} - 64

Find intervals:

Concave Upward

: - \infty < x < - \frac{4}{3},

Concave Downward

: - \frac{4}{3} < x < \frac{4}{3},

Concave Upward

: \frac{4}{3} < x < \infty

Plug

x = - \frac{4}{3}

into

x^{4} - 32 x^{2} + 5 : - \frac{1235}{9}

(- \frac{4}{3}, - \frac{1235}{9})

Plug

x = \frac{4}{3}

into

x^{4} - 32 x^{2} + 5 : - \frac{1235}{9}

(\frac{4}{3}, - \frac{1235}{9})

(- \frac{4}{3}, - \frac{1235}{9}), (\frac{4}{3}, - \frac{1235}{9})

f (x) = \frac{2}{x ^{\frac{1}{3}}} - 2

f (x) = \frac{1}{1 - x} + 1

f (x) = - 4 x + 3

f (x) = x^{2} + 3

f (x) = sin (2 x)

What is the inflection x^4-32x^2+5 ?
The inflection x^4-32x^2+5 is (-4/(sqrt(3)),-1235/9),(4/(sqrt(3)),-1235/9)