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Popular >

f(x)=-0.04x^2+40x+3500

Solution

f (x) = - 0.04 x^{2} + 40 x + 3500

Solution

Domain : - \infty < x < \infty

Range : f (x) \leq 13500

X Intercepts : (- 50 (315 - 10), 0), (50 (10 + 315), 0), Y Intercepts : (0, 3500)

Vertex : Maximum (500, 13500)

Inverse : - 5 (- x + 13500 - 100), 5 (- x + 13500 + 100)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, 13500]

Solution steps

Domain of

- 0.04 x^{2} + 40 x + 3500 : - \infty < x < \infty

Range of

- 0.04 x^{2} + 40 x + 3500 : f (x) \leq 13500

Axis interception points of

- 0.04 x^{2} + 40 x + 3500 :

X Intercepts

: (- 50 (315 - 10), 0), (50 (10 + 315), 0),

Y Intercepts

: (0, 3500)

Vertex of

- 0.04 x^{2} + 40 x + 3500 :

Maximum

(500, 13500)

Inverse of

- 0.04 x^{2} + 40 x + 3500 : - 5 (- x + 13500 - 100), 5 (- x + 13500 + 100)

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Frequently Asked Questions (FAQ)

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