What is the general solution for solvefor a,r=a(1-cos(θ)) ?

The general solution for solvefor a,r=a(1-cos(θ)) is a= r/(1-cos(θ));\quad θ\ne 2pin

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solvefor a,r=a(1-cos(θ))

solve for

a, r = a (1 - cos (θ))

a = \frac{r}{1 - cos ( θ )}; θ \neq = 2 πn

Solution steps

r = a (1 - cos (θ))

Switch sides

a (1 - cos (θ)) = r

Divide both sides by

1 - cos (θ); θ \neq = 2 πn

a = \frac{r}{1 - cos ( θ )}; θ \neq = 2 πn

f (x) = (x - 1) (x + 2) (x + 3)

y = - (x - 1)^{2} + 1

f (x) = (x - 1) (x + 2) (x - 3)

f (x) = (x + 2)^{2} (x - 3)^{2}

y = 2^{(x - 1)}

What is the general solution for solvefor a,r=a(1-cos(θ)) ?
The general solution for solvefor a,r=a(1-cos(θ)) is a= r/(1-cos(θ));\quad θ\ne 2pin