What is the midpoint (-1/2 , 3/2),(-15/2 ,-7/2) ?

The midpoint (-1/2 , 3/2),(-15/2 ,-7/2) is (-4,-1)

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midpoint (-1/2 , 3/2),(-15/2 ,-7/2)

midpoint

(- \frac{1}{2}, \frac{3}{2}), (- \frac{15}{2}, - \frac{7}{2})

(- 4, - 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- \frac{1}{2}, \frac{3}{2}), (x_{2}, y_{2}) = (- \frac{15}{2}, - \frac{7}{2})

= (\frac{- \frac{15}{2} - \frac{1}{2}}{2}, \frac{- \frac{7}{2} + \frac{3}{2}}{2})

Refine

= (- 4, - 1)

\frac{( x - 1 ) ^{2} ( x + 3 )}{3 x + 1}

f (x) = x^{2} + 2 x + 2

f (x) = \frac{1}{1 + e ^{- x}}

f (x) = - x + 6

f (x) = 2 x + 4 y = 8

What is the midpoint (-1/2 , 3/2),(-15/2 ,-7/2) ?
The midpoint (-1/2 , 3/2),(-15/2 ,-7/2) is (-4,-1)