What is the inverse of f(x)=-2x^2-2 ?

The inverse of f(x)=-2x^2-2 is sqrt(-(x+2)/2),-sqrt(-(x+2)/2)

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inverse of f(x)=-2x^2-2

inverse

f (x) = - 2 x^{2} - 2

- \frac{x + 2}{2}, - - \frac{x + 2}{2}

Solution steps

y = - 2 x^{2} - 2

Replace

x

with

y

x = - 2 y^{2} - 2

Solve for

y, x = - 2 y^{2} - 2

- \frac{x + 2}{2}, - - \frac{x + 2}{2}

f (x) = x - 1

\frac{4 - 5 x}{2 x}

x^{3} - 75 x

f (x) = 2 π x

f (x) = 9 x + 7

What is the inverse of f(x)=-2x^2-2 ?
The inverse of f(x)=-2x^2-2 is sqrt(-(x+2)/2),-sqrt(-(x+2)/2)