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Popular >

f(n)=e^{1/(2n)}

Solution

f (n) = e^{\frac{1}{2 n}}

Solution

Domain : n < 0 or n > 0

Range : 0 < f (x) < 1 or f (x) > 1

Intercepts : None

Asymptotes : Vertical n = 0, Horizontal y = 1

Extreme Points : None

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Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Range : (0, 1) \cup (1, \infty)

Solution steps

Domain of

e^{\frac{1}{2 n}} : n < 0 or n > 0

Range of

e^{\frac{1}{2 n}} : 0 < f (x) < 1 or f (x) > 1

Axis interception points of

e^{\frac{1}{2 n}} :

None

Asymptotes of

e^{\frac{1}{2 n}} :

Vertical

: n = 0,

Horizontal

: y = 1

Extreme Points of

e^{\frac{1}{2 n}} :

None

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y=(x^2+1)/(x-3)

y = \frac{x ^{2} + 1}{x - 3}

f(x)=(2x-2)/(x^2+2x-3)

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Frequently Asked Questions (FAQ)

What is the f(n)=e^{1/(2n)} ?
The f(n)=e^{1/(2n)} is