What is the perpendicular y= 4/7 x+5,(4,-7) ?

The perpendicular y= 4/7 x+5,(4,-7) is y=-7/4 x

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perpendicular y= 4/7 x+5,(4,-7)

perpendicular

y = \frac{4}{7} x + 5, (4, - 7)

y = - \frac{7}{4} x

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{4}{7} x + 5

that passes through

(4, - 7)

Find the slope of

y = \frac{4}{7} x + 5 : m = \frac{4}{7}

Compute the slope of the perpendicular line:

m_{p} = - \frac{7}{4}

Find the line with slope m=

- \frac{7}{4}

and passing through

(4, - 7) : y = - \frac{7}{4} x

y = - \frac{7}{4} x

f (x) = x^{2} + 2 x + 7

y = arcsin (x)

f (x) = - (x + 2)^{2} + 6

f (x) = - 4

7 x + 4 y = 14

What is the perpendicular y= 4/7 x+5,(4,-7) ?
The perpendicular y= 4/7 x+5,(4,-7) is y=-7/4 x