What is the f(x)=x^3-3x^2+1,-1/2 <= x<= 4 ?

The f(x)=x^3-3x^2+1,-1/2 <= x<= 4 is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(x)=x^3-3x^2+1,-1/2 <= x<= 4

f (x) = x^{3} - 3 x^{2} + 1, - \frac{1}{2} \leq x \leq 4

Domain : - \frac{1}{2} \leq x \leq 4

Range : - 3 \leq f (x) \leq 17

X Intercepts : (0.65270 \dots, 0), (2.87938 \dots, 0), Y Intercepts : (0, 1)

Asymptotes : None

Extreme Points : Minimum (- \frac{1}{2}, \frac{1}{8}), Maximum (0, 1), Minimum (2, - 3), Maximum (4, 17)

Interval Notation

Domain : [- \frac{1}{2}, 4]

Range : [- 3, 17]

Solution steps

Domain of

x^{3} - 3 x^{2} + 1, - \frac{1}{2} \leq x \leq 4 : - \frac{1}{2} \leq x \leq 4

Range of

x^{3} - 3 x^{2} + 1, - \frac{1}{2} \leq x \leq 4 : - 3 \leq f (x) \leq 17

Axis interception points of

x^{3} - 3 x^{2} + 1, - \frac{1}{2} \leq x \leq 4 :

X Intercepts

: (0.65270 \dots, 0), (2.87938 \dots, 0),

Y Intercepts

: (0, 1)

Asymptotes of

x^{3} - 3 x^{2} + 1, - \frac{1}{2} \leq x \leq 4 :

None

Extreme Points of

x^{3} - 3 x^{2} + 1, - \frac{1}{2} \leq x \leq 4 :

Minimum

(- \frac{1}{2}, \frac{1}{8}),

Maximum

(0, 1),

Minimum

(2, - 3),

Maximum

(4, 17)

f (x) = 4 - x^{2} + 1 + x

g (t) = (4 t^{2} - 3 t + 2)^{- 2}

f (x) = 6 + 2 + x

f (x) = (1 - x)^{\frac{2}{3}}

g (x) = sin (2 x)

What is the f(x)=x^3-3x^2+1,-1/2 <= x<= 4 ?
The f(x)=x^3-3x^2+1,-1/2 <= x<= 4 is