What is the domain of f(x)=(sqrt(x-4))/(x-8) ?

The domain of f(x)=(sqrt(x-4))/(x-8) is 4 8

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domain of f(x)=(sqrt(x-4))/(x-8)

domain

f (x) = \frac{x - 4}{x - 8}

4 \leq x < 8 or x > 8

Interval Notation

[4, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

4 \leq x < 8 or x > 8

y = 2 x - x^{2}

- 25 - x^{2}

\frac{x - 1}{x + 1}

y - 5 = - 3 (x - 17)

f (x) = 81 - x^{2}

What is the domain of f(x)=(sqrt(x-4))/(x-8) ?
The domain of f(x)=(sqrt(x-4))/(x-8) is 4<= x<8\lor x>8