What is the range of f(x)=x^2-11,x>= 0 ?

The range of f(x)=x^2-11,x>= 0 is f(x)>=-11

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range of f(x)=x^2-11,x>= 0

range

f (x) = x^{2} - 11, x \geq 0

f (x) \geq - 11

Interval Notation

[- 11, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x^{2} - 11, x \geq 0 : x \geq 0

Extreme Points of

x^{2} - 11, x \geq 0 :

Minimum

(0, - 11)

Find the range for the interval

0 \leq x < \infty : - 11 \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq - 11

f (x) = - 6 x + 3

f (x) = - x^{2} + 9

5 x^{2} - 48 x + 20

y = \frac{3}{4} x - 6

What is the range of f(x)=x^2-11,x>= 0 ?
The range of f(x)=x^2-11,x>= 0 is f(x)>=-11