What is the y= 1/(sqrt(x^2))-2x^4+3/(x^2) ?

The y= 1/(sqrt(x^2))-2x^4+3/(x^2) is

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y= 1/(sqrt(x^2))-2x^4+3/(x^2)

y = \frac{1}{x ^{2}} - 2 x^{4} + \frac{3}{x ^{2}}

Domain : x < 0 or x > 0

Range : - \infty < f (x) < \infty

X Intercepts : (\frac{3.18315 E 14}{2.5 E 14}, 0), (- \frac{3.18315 E 14}{2.5 E 14}, 0)

Asymptotes : Vertical x = 0

Extreme Points : None

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{1}{x ^{2}} - 2 x^{4} + \frac{3}{x ^{2}} : x < 0 or x > 0

Range of

\frac{1}{x ^{2}} - 2 x^{4} + \frac{3}{x ^{2}} : - \infty < f (x) < \infty

Axis interception points of

\frac{1}{x ^{2}} - 2 x^{4} + \frac{3}{x ^{2}} :

X Intercepts

: (\frac{3.18315 E 14}{2.5 E 14}, 0), (- \frac{3.18315 E 14}{2.5 E 14}, 0)

Asymptotes of

\frac{1}{x ^{2}} - 2 x^{4} + \frac{3}{x ^{2}} :

Vertical

: x = 0

Extreme Points of

\frac{1}{x ^{2}} - 2 x^{4} + \frac{3}{x ^{2}} :

None

f (t) = 14 t - sin (7 t) + e^{- 2 t}

g (y) = \frac{y - 1}{y ^{2} - y + 1}

f (x) = \frac{x + 2}{x ^{2} + 1}

f (x) = 6 x^{2} + 6 x - 36

f (- 2) = 2 x^{2} - x - 21

What is the y= 1/(sqrt(x^2))-2x^4+3/(x^2) ?
The y= 1/(sqrt(x^2))-2x^4+3/(x^2) is